Understanding T 2 + 7t + 2
What is T 2 + 7t + 2?
T 2 + 7t + 2 is an algebraic expression that is made up of three terms: T2, 7t, and 2.What does each term represent?
The first term, T2, is the product of a coefficient, T, and a variable, 2. The coefficient, T, is the number that is multiplied by the variable. In this case, the coefficient is T. The variable is the letter that stands in for a number. In this expression, the variable is 2. The second term, 7t, is a product of a coefficient, 7, and a variable, t. The coefficient is the number that is multiplied by the variable. The variable is the letter that stands in for a number. In this expression, the coefficient is 7 and the variable is t. The third term, 2, is a constant. A constant is a number that does not change.What does T 2 + 7t + 2 mean?
T 2 + 7t + 2 is an algebraic expression that represents the sum of three terms. The first term is the product of a coefficient, T, and a variable, 2. The second term is the product of a coefficient, 7, and a variable, t. The third term is a constant, 2.How do you solve for T 2 + 7t + 2?
To solve for T 2 + 7t + 2, you need to use the distributive property to expand the expression. For example, you can use the distributive property to expand the expression to T2 + 2T + 7t + 2. Once you have the expression expanded, you can use the order of operations to simplify it.Conclusion
T 2 + 7t + 2 is an algebraic expression that is made up of three terms. The first term is the product of a coefficient, T, and a variable, 2. The second term is the product of a coefficient, 7, and a variable, t. The third term is a constant, 2. To solve for T 2 + 7t + 2, you need to use the distributive property to expand the expression and then use the order of operations to simplify it.Related Video of T 2 + 7t + 2
Other Questions and Answers Related to T 2 + 7t + 2
1. jika t =3m-2,maka 2m-7t=
2m-7(3m-2) = 2m-21m+14 = 14-19m
2. 2(t+3)+(7t+3)=5(t-1) selesaikan
2t + 6 + 7t + 3 =5t -5
9t + 9 = 5t - 5
9t - 5t = -5-9
4t = -14
t = -14/4 = -3,52(t+3)+(7t+3) = 5(t-1)
2t + 6 + 7t +3 = 5t-5
2t + 7t - 5t = -6 - 3 - 5
4t = 14
t = 14/4
t = 7/2
3. 2(t+3)+(7t-3)=5(t-1)tolong slesaikan
2t + 6 + 7t - 3 = 5t - 5
2t + 7t - 5t = -5 - 6 + 3
4t = -8
t = -8 : 4
t = -2
(2t+5)+(9t-3)=(5t-4)
2t+9t-5t=5+3-4
11t-5t=6t
8-4=4
jawabanya = 6t 4
4. diket: w = 4t^5 + 7t^4 - 6t^3 + 2t^2 + t. t0 = 2s , t = 4s ditanya P...?
Soal
[tex]w = {4t}^{5} + {7t}^{4} - {6t}^{3} + {2t}^{2} + t[/tex]
Pembahasan.
P = W/t
[tex]p = \frac{dw}{dt} [/tex]
[tex]p = \frac{d}{dt} (4 {t}^{5} + {7t}^{4} - {6t}^{3} + {2t}^{2} + t)[/tex]
[tex]p = 20 {t}^{4} + 28 {t}^{3} - 18 {t}^{2} + 4t + 1[/tex]
[tex]p(0) = 20 ({0})^{4} + 28({0})^{3} - 18 ({0})^{2} + 4(0) + 1[/tex]
[tex]p(0) = 1[/tex]
[tex]p(4) = 20 {(4)}^{4} + 28 {(4)}^{3} - 18 {(4)}^{2} + 4(4) + 1[/tex]
[tex]p(4) = 5120 + 1729 - 288 + 16 + 1[/tex]
[tex]p(4) = 6579[/tex]
P = p(4) - p(0) = 6579 - 1
P = 6578 watt
5. Dik : r=5tpangkat 3 -6tpangkat 2 + 7t-12 Dit : v = ....? t= 1 sekon
v=dr/dt
= 15t^2-12t+7
= 15-12+7
=10 m/s
6. sebuah bola dilempar vertikal ke atas.Tinggi bola (h meter) setelah t detik dilemparkan dinyatakan dengan rumus h = 6 + 7t - 5t^2a.Hitunglah tinggi bola setelah 2 detik dilemparkan.b.Faktorkanlah berbentuk 6+7t-5t^2 kemudian gantilah t dengan 2!bandingkan jawabannya dengan hasil jawaban a!
Penjelasan dengan langkah-langkah:
a. t = 2 DETIK
h = 6 + 7(2) - 5(2)^2
h = 6+14-20
h = 0
b. 6+7t-5t^2
= 6+10t-3t-5t^2
= 2(3+5t)-1t(3+5t)
= (2-1t) (3+5t)
t = 2=====>. (2-1(2)) (3+5(2)) = 0
hasil sama yaitu 0
7. tentukan nilai dari 5(t²+1)-7t=0
Jawab:
Penjelasan dengan langkah-langkah:
5(t²+1)-7t=0
= 5t² + 5 - 7t = 0
5t ( t + 1 ) - 7t = 0
5t - 7t ( t + 1 ) = 0
-2t ( t + 1 ) = 0
-2t - 2 = 0
-2(t + 1 ) = 0
t + 1 = 0
t = -1
8. Tentukan Penyelesaian PK berikut ini x+3x+2=0 t-7t+12=0 -t+3t
A.x+3x+2=0
x+3x=-2
4x=-2
x=-2/4
x=-1/2
B.t-7t+12=0
t-7t=-12
-8t=-12
t=12/8
t=3/2(1 1/2)
C.-t+3t=2t
9. tentukan nilai dari (2-7t)(4t-1) jika t=1!
t=1
(2-7t)(4t-1)
=(2-7(1))(4(1)-1)
=(2-7)(3)
=(-5)(3)
=-15
Semoga membantu(:jika t = 1
(2 - 7t)(4t - 1) =
(2 - 7(1))(4(1)- 1) =
(2-7)(4-1) =
(-5)(-3)=
15
10. Diketahui f(t) = sin 5t - 2 cos 6t + cos 7t. Hasil dri f' (π/2)
[tex]f(t) = \sin(5t) - 2 \cos(6t) + \cos(7t) \\ f'(t) = 5 \cos(5t) + 12 \sin(6t) - 7 \sin(7t) \\ f'( \frac{\pi}{2} ) = 5 \cos( \frac{5\pi}{2} ) + 12 \sin(3\pi) - 7 \sin( \frac{7\pi}{2} ) \\ f'( \frac{\pi}{2} ) =5(0) + 12(0) - 7( - 1) \\ f'( \frac{\pi}{2} ) = 7[/tex]
semoga membantu
11. f(t)=t³-7t²+18t-10g(t)=-t³-7t²-18t-10tentukan:a.f(t)+g(t)b.f(t)-g(t)c.f(t).g(t)
Jawaban:
\begin{gathered}3f(t) - 2g(t) \\ =3 ( {t}^{3} - 7 {t}^{2} + 18t - 10 ) -2 ( - {t}^{3} - 7 {t}^{2} - 18t + 10 ) \\ = 3{t}^{3} + 2{t}^{3} - 21 {t}^{2} + 14 {t}^{2} + 54t + 36t - 30 - 20 \\ = 5 {t}^{3} - 7 {t}^{2} + 100t - 50\end{gathered}
3f(t)−2g(t)
=3(t
3
−7t
2
+18t−10)−2(−t
3
−7t
2
−18t+10)
=3t
3
+2t
3
−21t
2
+14t
2
+54t+36t−30−20
=5t
3
−7t
2
+100t−50
12. t²+7t= -10 Mohon dijawab secepatnya!!
[tex]t x^{2} + 7t +10 = 0 (t+5) (t+2) = 0 t= -5 atau t= -2[/tex]t² + 7t = -10
⇒ t² + 7t + 10 = 0
⇒ (t + 2)(t + 5) = 0
maka
t + 2 = 0 ⇒ t = -2
t + 5 = 0 ⇒ t = -5
Jadi,
HP = {-2, -5}
Terimakasih semoga membantu
13. 12-7t+t² ,,,,, terima kasih
faktorkan
t² - 7t + 12 = (t - 4)(t - 3)
14. limit (t²+7t+7)/(t²-4t-5) untuk t mendekati -1 adalah
Jawaban:
cba krjakan ulang yaa biar lbh paham
15. 1. 5t + 6t =..2.t-7t=..3.4r= -28
[tex]1. \: \: 5t + 6t \\ = 11t[/tex]
[tex]2. \: \: t - 7t \\ = - 6t[/tex]
[tex]3. \: \: 4r = - 28 \\ r = \frac{ - 28}{4} \\ r = - 7[/tex]
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16. tentukan nilai (2-7t)(4t-1)jika t=1!
(2-7(1))(4(1)-1)= (2-7)(4-1)= -5 x 3= -15
{2-7(1)}{4(1)-1}
=(2-7)(4-1)
=(-5)(3)
= -15
Smoga membantu
17. 2(t+3) = 5(t-1)-7 (+ -3)2t + 6 = 5+ -5 - 7t + 212t + 6 =
Jawaban:
2t + 6 = -7t + 21
9t = 15
3t = 5
t = 1 2/3
18. 4. 7t + 6 = 27, maka nilai t adalah...
[tex]7t + 6 = 27 \\ 7t = 27 - 6 \\ 7t = 21 \\ t = \frac{21}{7} \\ t = 3[/tex]
Jawaban:
3
Penjelasan dengan langkah-langkah:
7t + 6 = 27
27 - 6 = 21
21 ÷ 7 = 3
jadi, 7x3+6=27
maaf kalau salah
19. tentukan nilai t dari 7t-1=24+6t
Penjelasan dengan langkah-langkah:
[tex] \tt7t - 1 = 24 + 6t[/tex]
Maka dapat kita ubah persamaan tersebut menjadi :
[tex] \tt7t - 6t = 24 + 1[/tex]
Kurangkan suku sejenis
[tex]{ \boxed{ \boxed{ \tt t = 25}}}[/tex]
20. tentukan nilai dari (2×7t)(4t-1) t=1
(2*(7*1))*((4*1)-1)=14*3=42 dimasukkan dulu x nya kedalam operasi hitungnya
