Introduction to 3 x 4 = 12
What is Multiplication?
Multiplication is a basic mathematical operation that involves taking two or more numbers and multiplying them together. It is one of the four basic operations of arithmetic, along with addition, subtraction, and division.How Does Multiplication Work?
When two numbers are multiplied together, the result is the total amount of all the numbers multiplied together. For example, when we multiply 3 x 4, the result is 12. This means that we have taken 3 four times and added them together to get 12.What is 3 x 4 = 12?
3 x 4 = 12 is a multiplication equation that states that when 3 is multiplied by 4, the result is 12. This equation can be written in several different forms, such as 3 x 4 = 12 or 3 * 4 = 12.Example Problem:
If we have 3 apples and 4 oranges, how many pieces of fruit do we have in total?Solution:
We can use the equation 3 x 4 = 12 to solve this problem. Since we have 3 apples and 4 oranges, we can multiply 3 and 4 together to get 12. Therefore, we have 12 pieces of fruit in total.Conclusion
3 x 4 = 12 is a multiplication equation that states that when 3 is multiplied by 4, the result is 12. This equation can be used to solve problems involving the multiplication of two numbers.Related Video of 3 X 4 2 2x 1
Other Questions and Answers Related to 3 X 4 2 2x 1
1. 1. | x-7 | = | 3x-1 |2.| 3+2x | = | 4-x |3. | 3x+2 | = | 2x-3 |4. | x-2 | = | 2x+1 |5. | 1-2x | = | 4-x |
belum tentu benar nih
1. x-7=3x-1
-2x=6
x=-3
x-7=-3x+1
4x=8
x= 2
2. 3+2x=4-x
3x=1
x=1/3
3+2x=-4+x
x=-7
3. 3x+2 = 2x-3
x=-5
3x+2=-2x+3
5x=1
x= 1/5
4. x-2 = 2x+1
-x=3
x=-3
x-2=-2x-1
3x=1
x=1/3
5. 1-2x = 4-x
-x=3
x=-3
1-2x=-4+x
-3x = -5
x= 5/3
kelas 10 ya ?
2. hasil dari 1/x-1-1/2x+2 adalaha.x+4/(x-1)(2x+3)b.x+2/(x-1)(2x+3)c.x-2/(x-4)(2x+3)d.2-x/(x-1)(2x+3)
kalikan 1/x-1 x -1/2x+2
gabungkan suku suku menggunakan penyebut yang sama 1/x+1/2x+2=
2+1+4x/ 2x klo hasilnya di tambah jd 3 + 4x / 2x
a.
3. 1. x-3 per 2 = 2x + 4 per 5 2. 3 per x - 4 per 5x = 1 per 10 3. 2x + 3 per 2x - 4 = x - 1 per x + 1
1. x-23
2. 3/x - 4/5x = 1/10
agar lebih sederhana dan mudah. kita kalikan mereka dengan x, jadi
3 - 4/5 = 1/10x
15/5 - 4/5 = 1/10x
11/5 = 1/10x
110/5 = x
22 = x
3. 11x - 1
4. 1. | 2x+3 | ≤ | x-2| 2. 2 | x | + | x-1 | ≤ 2 3. x | x | ≤ | x-1 | 4. | 2x-3 | ≤ | x+2 |
1. -5<=x<=-1/3
2. -1/3<=x<=1
3. ....
4. 1/3<=x<=5
5. tentukan nilai x dari persamaan berikut ini ! 1). 3x + 4 =132). 2(x+4)=163). 4x +2 = 2x +104).2(x-4)=4(x+4)5).2x+3 PER 2 = 66).3x+2 PER 3 = 2x -1 PER 2 =7).4(X+1)-2X=128).1/3 (6x +9 ) =1/4 (2x +4)9). 2-3 (1-2x) = 5-2 (2x+3)10). 2x -11 Per 3 +5 = 1+x per 2 - 4
semoga membantu
itu bru no 5
6. diketahui g(x-2)= 2x/x+1 ;x≠-1. rumus fungsi g(x)=........... a. 2x+4/x+3 ;x≠-3 b. 2x+4/x-3 ;x≠3 c. 2x-4/x-3 ;x≠3 d. 2x/x-2;x≠2 e. x-2/x-1 ;x≠1
Fungsi Komposisi
g(x - 2) = (2x)/(x +1)
x - 2= y
x = y + 2
g(y) = { 2(y +2)} / (y +2 + 1)
g(y) = (2y + 4)/(y + 3)
g(x) = (2x + 4) /(x + 3) , x ≠ - 3
7. 1. (x+2) (x+3) 2.(2x+1) (2x-1) 3.(x-4) (-x-1)
1. (x+2) (x+3)
= x² + 3x + 2x + 6
= x² + 5x + 6.
2.(2x+1) (2x-1)
= 4x² - 2x + 2x - 1
= 4x² - 1.
3.(x-4) (-x-1)
= -x² - 1x + 4x + 4
= -x² + 3x + 4.
8. Jawab soal dibawah ini dengan jelas dan singkat. 1. | 2x + 4 | + 2 = 3 2. | 1/2x + 2 | -2 = 4 3. | 2x + 4 | = | x + 1 | 4. 2 | x - 1 | = | x + 1 | 5. | 2x + 1 | = | x - 1 | + 2 6. | x + 4 | - | x + 1 | = 3
[tex]\boxed{\boxed{\bold{Penyelesaian~Soal~!}}}}}[/tex]
1. | 2x + 4 | + 2 = 3
2x + 4 = 1
6x = 1
x = [tex]\frac{1}{6}[/tex]
| 2x + 4 | + 2 = -3
| 2x + 4 | = -5
6x = 5
x = [tex]\frac{5}{6}[/tex]
Hp = [tex]\{\frac{5}{6}, \frac{1}{6}\}[/tex]
2. | [tex]\frac{1}{2}[/tex]x + 2 | -2 = 4
[tex]\frac{1}{2}[/tex]x + 2 = 6
1x = 6
x = [tex]\frac{6}{1}[/tex]
x = 6
| [tex]\frac{1}{2}[/tex]x + 2 | -2 = -4
| [tex]\frac{1}{2}[/tex]x + 2 | = -2
1x = -2
x = [tex]\frac{-2}{1}[/tex]
x = -1
Hp = {-1,6}
3. | 2x + 4 | = | x + 1 |
(2x + 4)² = (x + 1)²
4x² + 16 + 16= x² + 16 + 1
4x² - 64 = 0
x² - 16 = 0
(x + 4)(x - 4) = 0
x = -4 atau x = 4 = 0
HP = {-4, 4}
4. 2 | x - 1 | = | x + 1 |
(2x - 1)² = (x + 1)²
4x² - 4 + 1 = x² + 4 + 1
x² - 4 = 0
(x + 2) (x - 2) = 0
x = -2 x = 2
Hp = {-2 ,2}
5. | 2x + 1 | = | x - 1 | + 2
(2x + 1)² = (x - 1)² + 2
4x² + 4 + 1 = x² - 4 + 1 + 2
x² + 4 - 6 = 0
x² + -2 = 0
(x + 1) (x - 2) = 0
x = -1 x = 2
HP = {-1, 2}
6. | x + 4 | - | x + 1 | = 3
(x + 4)² - (x + 1)² = 3
2x + 8 + 16 - 2x + 2 + 1 = 3
4x² + 16 + 16 = 3
4x² - 64 = 3
x² - 16 + 3 = 0
x² - 13 = 0
(x - 1) (x + 13) = 0
x = 1 x = -13
Hp = {1,-13}
[tex]\boxed{\boxed{\bold{Pembahasan~Soal~}}}}}[/tex]
Definisi nilai mutlak :
|x| = x jika x ≥ 0
|x| = -x jika x < 0
[tex]|x| = \sqrt{x^2}[/tex]
Persamaan nilai mutlak (c > 0)
1) |ax + b| = c
=> ax + b = c atau ax + b = -c
2) |ax + b| = |cx + d|
=> (ax + b)² = (cx + d)²
Pertidaksamaan nilai mutlak (a > 0, c > 0)
1) |ax + b| < c
=> -c < ax + b < c
2) |ax + b| > c
=> ax + b < -c atau ax + b > c
3) |ax + b| < |cx + d|
=> (ax + b)² < (cx + d)²
✍✍✍✍✍✍✍✍✍✍✍✍✍✍✍✍✍✍✍✍
Pelajari Lebih Lanjut Materi Tentang Nilai MutlakUntuk contoh soal lainnya, bisa dilihat di link berikut
brainly.co.id/tugas/7303969
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Detail JawabanKelas : 10
Mapel : Matematika
Kategori : Persamaan dan Pertidaksamaan linear nilai mutlak satu variabel
Kata Kunci : Definisi Nilai Mutlak
Kode : 10.2.1
9. |x-7|=|2x-2| |x-3|=|x+2| |x-3|=|3-x| |2x-1|=|4x+9| |x-2|=3x+1 |4x+3|=3-x |2x-4|=4-2x |x-3|=|3x+2 |
#Lebihdetailnyacaridigoogle
10. 1.√2x-4<2 2.√4-x>3 3.√x<2 4.√3-2x<5 5.√2x+5>2
Jawaban:
cba krjakan ulang lgi yaa biar lbh paham
11. 1. (2x - 3) (x +2)2. (x + 4) (x - 4)3. (x + 3)4. (2x - 5)2?
Penjelasan dengan langkah-langkah:
semgagqgqgaqq benananarrr yayayayyayaa
12. 1. |x + 4| + |x - 4|2. |2x - 3| - |x - 2|3. |-x + 4| + |5 + 2x|4. |4 - 2x| - |2x + 4|5. |x + 3| - |x - 3|
Penjelasan dengan langkah-langkah:
1. (x + 4) + (x - 4) = x + 4 + x - 4 = 2x
2. (2x - 3) - (x - 2) = 2x - 3 - x + 2 = x - 1
3. (- x + 4) + (5 + 2x) = - x + 4 + 5 + 2x = x
+ 9
4. (4 - 2x) - (2x + 4) = 4 - 2x - 2x - 4 = - 4x
5. (x + 3) - (x - 3) = x + 3 - x + 3 = 6
13. Tentukan hasil dari aljabar berikut ini 1.(x-1)(x-2) 2.(x+2)(x-2) 3.(2x-1)(x+2) 4.(3x-1)(x+3) 5.(2x-4)(2x+4)
ini jawabannya menurut saya
14. 1.(x+3) (x-2) =2.(x-5) (x-3) =3.(x+2) (2x-1) =4.(2x-3) (x+-1) =5.(x+4) (2x-1) =6.(2x-3) (x-2) =7.(3x+1) (2x+3) =8.(2x-1) (2x+3) =9.(2x+3) (x+2y-3) =10.(3-2x) (1+3x) =Tolong jawab ya...
semoga membantuuuuuuu^^
15. 1. (4x - 2) - (2x - 4) = 2. (3x + 2) - (2x - 1) =3. (3x - 3) + (2x - 1) =4. (x+2) + (x+2) = 5. (2x + 2) + (x + 3) =
Materi : Bentuk Aljabar
Soal Nomor 14x - 2 -( 2x - 4 )
4x - 2 - 2x + 4
( 4 - 2 )x + 2
2x + 2
Soal Nomor 23x + 2 -( 2x - 1 )
3x + 2 - 2x + 1
( 3 - 2 )x + 3
x + 3
Soal Nomor 33x - 3 + 2x - 1
( 3 + 2 )x - 4
5x - 4
Soal Nomor 4x + 2 + x + 2 )
( 1 + 1 )x + 4
2x + 4
Soal Nomor 52x + 3 + x + 3
( 2 + 1 )x + 6
3x + 6
Semoga bisa membantu
[tex] \boxed{ \colorbox{lightblue}{ \sf{ \color{blue}{ Answer By\:BlueBraxGeometry}}}} [/tex]
1. (4x - 2) - (2x - 4)
= 4x - 2 - 2x + 4
= 4x - 2x - 2 + 4
= 2x + 2
2. (3x + 2) - (2x - 1)
= 3x + 2 - 2x + 1
= 3x - 2x + 2 + 1
= 1x + 3
= x + 3
3. (3x - 3) + (2x - 1)
= 3x - 3 + 2x - 1
= 3x + 2x - 3 - 1
= 5x - 4
4. (x+2) + (x+2)
= x + 2 + x + 2
= x + x + 2 + 2
= 2x + 4
5. (2x + 2) + (x + 3)
= 2x + 2 + x + 3
= 2x + x + 2 + 3
= 3x + 5
16. 1. (2x - 3)(x +2)2. (x + 4) (x-4)3. (x + 3)24. (2x - 5)2
Jawaban:
1.2x*2+x-6
2.x*2-16
3.2x+6
4.4x-10
17. 1)2x² x -2 + 1= 2)2x² x -1 +1= 3)2x² x 0 + 1= 4)2x² x 1 +1= 5)2x² x 2 +1= 6)2x² x 3 +1=
1. 2x² × -2 + 1 = -4x² + 1
2. 2x² × -1 + 1 = -2x² + 1
3. 2x² × 0 + 1 = 1
4. 2x² × 1 + 1 = 2x² + 1
5. 2x² × 2 + 1 = 4x² + 1
6. 2x² × 3 + 1 = 6x² + 1
Sorry kalo ada yang salah. :)1)2x² x -2 +=-4x²+1
2)2x² x -1 +1=-2x²+1
3)2x² x 0 +1=1
4)2x² x 1 +1=2x²+1
5)2x² x 2 +1=4x²+1
6)2x² x 3 +1=6x² +1
18. 1. lim x²+2x-3/2x-3 x→12. lim 2x²-x-3/x²-3 x→13. lim x³-2x²/x²-4 x→2
Jawaban:
1. x²+2x-3/2x-3
= 1²+2.1-3/2.1-3
= 1+2-3/2-3
= 3-3/2-3
= 0/-1
= 0
2. 2x²-x-3/x²-3
= 2.1²-1-3/1²-3
= 2-1-3/1-3
= -2/-2
= 1
3. x³-2x²/x²-4
= 3x²-4x/2x
= 3.2²-4.2/2.2
= 12-8/4
= 4/4
= 1
semoga membantu
19. 1. |2x - 7| = 32. |2x - 1| = |x + 4|3. |x - 2| = 2x + 14. |x - 2| + |2x + 6| =5. |x +1| + |2x -4| = 9:v
Jawab:
Penjelasan dengan langkah-langkah:
1. |2x - 7| = 3 ⇒(2x - 7)² = 3²
((2x - 7)-3)((2x-7)+3)=0
(2x-10)(2x-4)=0
x=5 atau x=2
2. |2x - 1| =|x+4| ⇒(2x - 1)² = (x+4)²
4x²-4x+1=x²+8x+16
3x²-12x-15=0⇒x²-4x-5=0
(x-5)(x+1)
x=5 atau x=-1
20. Dari pemfaktoran berikut :(1) x² - 4 = (x+2)(x-2)(2) x² - 2x -3 = (x+3)(x-1)(3) x² + 2x-8 = (x+4)(x-2)(4) 2x² + 3x - 2 = (2x+1)(x-2)Pemfaktoran yang benar adalah....a.(1) dan (2)b.(1) dan (3)c.(2) dan (3)d.(2) dan (4)
Jawaban:
B. 1 dan 3
Penjelasan dengan langkah-langkah:
(1) x² - 4 = (x+2)(x-2)(Benar)
(x+2)(x-2)
= x² - 2x + 2x - 4
= x² - 4
(2) x² - 2x -3 = (x+3)(x-1)(salah)
(x+3)(x-1)
= x² - x + 3x - 3
= x² + 2x - 3
(3) x² + 2x-8 = (x+4)(x-2)(Benar)
(x+4)(x-2)
= x² - 2x + 4x - 8
= x² + 2x - 8
(4) 2x² + 3x - 2 = (2x+1)(x-2)(salah)
(2x+1)(x-2)
= 2x² - 2x + x - 2
= 2x² - x - 2
